Calculating match attendance

The user expressed a fact in Chinese about the total attendance for the 2025 FA Cup, which is 505,278, with an average of 8,020 per match. I’m considering whether they want to calculate the number of matches, which I'd find by dividing the total by the average. The math gives me roughly 63 matches, but there’s a small discrepancy of 18 people due to rounding. I think they might be checking for consistency in these numbers.Verifying match calculations

I'm looking into the number of matches based on the given average of 8,020. If we consider that average as exact, dividing 505,278 by 8,020 gives about 63 matches, but matches should be whole numbers. If I assumed 63 matches, the implied average would actually be around 8,022.5, leading me to see that rounding is at play. After recalculating, I found the average aligns with 8,020 when rounded. It seems like a straightforward math problem, so I can share the calculations confidently.Summarizing attendance calculations

I’m thinking about computing the median, but it seems there isn’t enough information for that at the moment. I’m focusing on crafting a concise answer in Chinese regarding the total attendance of 505,278 and average attendance of 8,020.

So, if we divide to find the number of matches, it’s approximately 63, accounting for rounding errors. I also see the alternative of 64 matches isn’t viable as it doesn’t match the average. I’ll keep it simple and present it cleanly!

按你给的数据可推算出比赛场次：

• 场次 ≈ 505,278 ÷ 8,020 ≈ 63.02 → 实际应为 63 场（场次数必须是整数）
• 验证：63 × 8,020 = 505,260，与总数相差 18 人，属于场均四舍五入造成的差异
• 精确场均应为：505,278 ÷ 63 ≈ 8,020.29 人（四舍五入为 8,020）